1) Write mxy2=0 in the form y=mxc 2) work out equation of circle 3) Subsitute y=mx2 into the y in the equation of the circle 4) Expand and simplify 5) factor out x so in brackets you get m and numbers only 6) work out discriminant (b^24ac) 7) sub into m 5Y = mx c is an important reallife equation The gradient, m, represents rate of change (eg, cost per concert ticket) and the yintercept, c, represents a starting value (eg, an admin fee)If (x y)^3 (x y)^3 6y(x^2 y^2) = ky^2 , then k = Click here👆to get an answer to your question ️ If (x y)^3 (x y)^3 6y(x^2 y^2) = ky^2 , then k = Join / Login maths If (xy)3−(x−y)3−6y
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(x y)^3-(x-y)^3-6y(x^2-y^2)=ky^2
(x y)^3-(x-y)^3-6y(x^2-y^2)=ky^2-3/x2/y=0 take lcm or multiply both lhs and rhs with xy 3y2x=0 3y=2x substitute 3y=2x in the other equation 2/x2/(2x)=1/6 2/x1/x=1/6 as they are like fractions we can perform subtraction 1/x=1/6 therefore x=6 and substituting x=6 in any eqn3 X Y x=y2 y=x2 (1,1) (4,2) Figure 2 The area between x = y2 and y = x − 2 split into two subregions If we slice the region between the two curves this way, we need to consider two different regions Where x > 1, the region's lower bound is the straight line For x < 1, however, the region's lower bound is the lower half of the
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Xy=6;x3y=6 Simple and best practice solution for xy=6;x3y=6 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your own Stepbystep explanation since x=3and y=2 by putting values of x and y in our equation we get 4x6y=4 (3)6 (2) since (1)× (1)=1 =4×36×2 =1212 =24 H O P E I T H E L P S Y O U P L Z ZGraph x^2y^24x6y3=0 Add to both sides of the equation Complete the square for Tap for more steps Use the form , to find the values of , , and to those of the standard form The variable represents the radius of the circle, represents the xoffset from the origin, and represents the yoffset from origin The center of the circle
The simultanous equation calculator helps you find the value of unknown varriables of a system of linear, quadratic, or nonlinear equations for 2, 3,4 or 5 unknowns A system of 3 linear equations with 3 unknowns x,y,z is a classic example This solve linear equation solver 3 unknowns helps you solve such systems systematicallySystemofequationscalculator 2xy=6, 2yy=2 en Related Symbolab blog posts Middle School Math Solutions – Simultaneous Equations Calculator Solving simultaneous equations is one small algebra step further on from simple equations Symbolab math solutionsLet y=0 and solve for x, this is your xintercept 3x3 (0)=6 3x=6 3x/3=6/3 x=2 Plot (2,0) Notice that is the same xintercept that L1 had L1 is lying right ontop of L2, in other words they graphically are the same line The solution is all real numbers
যদি (xy)^(3)(xy)^(3)6y(x^(2)y^(2))=ky^(2) , তারপরে কে = Updated On 23 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!Start your free trial In partnership with You are being redirected to Course Hero I want to The factored form is (x3y)(xy) You can treat it like a quadratic, where instead of constant numbers, there are y terms First, find two numbers that multiply to 3 (the c value of the "quadratic") and add up to 2 (the b value of the "quadratic") These two numbers are 3 and 1 Split the middle term into these two numbers Then, factor the first two and last two terms
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Find stepbystep Calculus solutions and your answer to the following textbook question For what value of k are the two lines 2x ky = 3 and x y = 1 parallel?Subtract x^ {3} from both sides Subtract x 3 from both sides Combine x^ {3} and x^ {3} to get 0 Combine x 3 and − x 3 to get 0 Reorder the terms Reorder the terms This is true for any x This is true for any x Use the distributive property to multiply xy by x^ {2}xyy^ {2This calculator will try to solve the system of 2, 3, 4, 5 simultaneous equations of any kind, including the polynomial, rational, irrational, exponential
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The quadratic x2 2x3 = 0 has no real solutions, so the only solution to the cubic equation is obtained by putting x− 1 = 0, giving the single real solution x = 1 The graph y = x3 x2 x− 3 is shown in Figure 4 2 1 2 3 x y 324 Figure 4 The graph of y = x3 x2 x− 3 You can see that the graph crosses the xaxis in oneSolution 1 First assume y 2 =ux 2, and y 2 '=2uxu'x 2 and y 2 ''=u''x 2 4u'x2u Substituting into x 2 y''2xy'6y=0 we get x 2 (u''x 2 4u'x2u)2x(2uxu'x 2)6y=0 and simplifying by adding like terms we get u''x 4 6u'x 3 =0 We reduce the order by w=u' to get w'x 4 6wx 3 =0 Now dividing by wx 4 and rearranging, we get and integrating bothWatch Video in App This browser does not support the video element 348 k 17 k Answer
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Math Input NEW Use textbook math notation to enter your math Try itSubstitute x in terms of y into the first equation (2y6) 2 y 2 =36 Use FOIL to expand the brackets 4y 2 24y36y 2 =36 => 5y 2 24y=0 y(5y24)=0 => y=0 or y=(24)/5 Substitute these values of y into the second equation to find x when y=0, x=2*06 => x=6 when y=(24)/5, x=2*(24)/56 => x=36(2 x) dy dx = 3y This is a First Order separable Differential equation, and we can rearrange as follows 1 y dy dx = 3 x 2 And we can "separate the variables" to get ∫ 1 y dy = ∫ 3 x 2 dx
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The given equation is (x y) 3 − (x − y) 3 − 6y (x 2 − y 2) = ky 2 Recall the formula `a^3 b^3 = (ab) (a^2 ab b^2)` Using the above formula, we have ` (xy)^3 (xy)^3 6y (x^2 y^2 )ky^2` `⇒ { (xy)^3 (xy)^3} 6y (x^2 y^2) = ky^2`Then type x=3 Try it now 2x @ x=3 Clickable Demo Try entering 2x @ x=3 into the text box After you enter the expression, Algebra Calculator will evaluate 2x for x=3 2(3) = 6 More Examples Here are more examples of how to evaluate expressions in Algebra Calculator Feel free to try them now Evaluate 3xy for x=2, y=3 3xy @ x=2, y=3Divide y, the coefficient of the x term, by 2 to get \frac{y}{2} Then add the square of \frac{y}{2} to both sides of the equation This step makes the left hand side of the equation a perfect square
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2 3\pi e x^{\square} 0 \bold{=} Go Related » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!\(x = 3\) and \(y = 4\) To be able to solve an equation like this, another equation needs to be used alongside it That way it is possible to find the only pair of values that solve both equationsMath Input NEW Use textbook math notation to enter your math Try it
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Differential Equation Calculator The calculator will try to find the solution of the given ODE firstorder, secondorder, nthorder, separable, linear, exact, Bernoulli, homogeneous, or inhomogeneous Initial conditions are also supported Your input solve $$$ y ' \left (x \right) = x^ {2 $\begingroup$ You actually have a function z = F (x, y) and the criterion of the second derivative applies similarly to when it has a function y = f (x) In this case, when there is, say, a minimum (graphically), you can see that as the variable grows, the value of the derivative (ie the value of the tangent) goes from zero (at the extreme point) to a positive value, that is, the Ex , 3 Find the area of the region bounded by the curves 𝑦=𝑥22, 𝑦=𝑥, 𝑥=0 and 𝑥=3 Here, 𝑦=𝑥22 𝑦−2=𝑥^2 𝑥^2=(𝑦−2) So, it is a parabola And, 𝑥=𝑦 is a line x = 3 is a line x = 0 is the yaxis Finding point of intersection B & C Point B Point B is intersection
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#12 Report Thread starter 1 year ago #12 (Original post by chibichibi_xx) The answers given there are just an example of how you should write them, they're not the actual answersUsed Wolfram Alpha and got x=09,y=23 , x=14,y=92 Last edited by chibichibi_xx;First type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More Examples
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30 a 1 x b 1 y c 1 = 0 and a 2 x b 2 y c 2 = 0, where a 1, b 1, c 1, a 2, b 2, c 2 are all real numbers and a 1 2 b 1 2 ≠ 0, a 2 2 b 2 2 ≠ 0, is called a (a) family of two different straight lines (b) family of two coincident lines (c) pair of linear equations in two variables (d) none of these Answer/Explanation Answer c1 year ago 0 reply iizhaque Badges 6 Rep?This means k^2 3k 2 = 0 =(k1)(k2) If 2 things multiply to give zero then at least one of them must be zero so we can have k=1 or k=2 Therefore any solution of the form y = Ae^x Be^(2x) where A and B are constants solves y'' 3y' 2y = 0 Now we need the particular integral Since the right hand side of y'' 3y' 2y = 2e^x has an e
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Solvevariablecom contains valuable facts on solve for y calculator, solving exponential and quadratic function and other algebra subjects In cases where you have to have advice on mixed numbers or even grade math, Solvevariablecom is simply the ideal site to explore! Click here 👆 to get an answer to your question ️ (k3)x3y=k kxky=12 determine the value of k for which the given system of equations has infinitely many afirasyed39 afirasyed39Simple and best practice solution for x2y=6;xy=3 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework
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Example If the lines 2x y – 3 = 0, 5x ky – 3 = 0 and 3x – y – 2 = 0 are concurrent, find the value of k Three lines are concurrent if they pass through a common point ie point of intersection of any two lines lies on the third line It is given that lines 2x y − 3 = 0 5xUse the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the axis Sketch the region and aCompleting the square of an expression with multiple variables is a technique which manipulates the expression into a perfect square plus some constant As an example, x 2 2 x y 2 − 6 y z 2 − 8 z 1 x^22xy^26yz^2 8z 1 x2 2xy2 −6y z2 −8z 1 can be written in the complete square form as ( x 1) 2 ( y − 3) 2 ( z
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