1) Write mxy2=0 in the form y=mxc 2) work out equation of circle 3) Subsitute y=mx2 into the y in the equation of the circle 4) Expand and simplify 5) factor out x so in brackets you get m and numbers only 6) work out discriminant (b^24ac) 7) sub into m 5Y = mx c is an important reallife equation The gradient, m, represents rate of change (eg, cost per concert ticket) and the yintercept, c, represents a starting value (eg, an admin fee)If (x y)^3 (x y)^3 6y(x^2 y^2) = ky^2 , then k = Click here👆to get an answer to your question ️ If (x y)^3 (x y)^3 6y(x^2 y^2) = ky^2 , then k = Join / Login maths If (xy)3−(x−y)3−6y
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(x y)^3-(x-y)^3-6y(x^2-y^2)=ky^2
(x y)^3-(x-y)^3-6y(x^2-y^2)=ky^2-3/x2/y=0 take lcm or multiply both lhs and rhs with xy 3y2x=0 3y=2x substitute 3y=2x in the other equation 2/x2/(2x)=1/6 2/x1/x=1/6 as they are like fractions we can perform subtraction 1/x=1/6 therefore x=6 and substituting x=6 in any eqn3 X Y x=y2 y=x2 (1,1) (4,2) Figure 2 The area between x = y2 and y = x − 2 split into two subregions If we slice the region between the two curves this way, we need to consider two different regions Where x > 1, the region's lower bound is the straight line For x < 1, however, the region's lower bound is the lower half of the
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Xy=6;x3y=6 Simple and best practice solution for xy=6;x3y=6 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your own Stepbystep explanation since x=3and y=2 by putting values of x and y in our equation we get 4x6y=4 (3)6 (2) since (1)× (1)=1 =4×36×2 =1212 =24 H O P E I T H E L P S Y O U P L Z ZGraph x^2y^24x6y3=0 Add to both sides of the equation Complete the square for Tap for more steps Use the form , to find the values of , , and to those of the standard form The variable represents the radius of the circle, represents the xoffset from the origin, and represents the yoffset from origin The center of the circle
The simultanous equation calculator helps you find the value of unknown varriables of a system of linear, quadratic, or nonlinear equations for 2, 3,4 or 5 unknowns A system of 3 linear equations with 3 unknowns x,y,z is a classic example This solve linear equation solver 3 unknowns helps you solve such systems systematicallySystemofequationscalculator 2xy=6, 2yy=2 en Related Symbolab blog posts Middle School Math Solutions – Simultaneous Equations Calculator Solving simultaneous equations is one small algebra step further on from simple equations Symbolab math solutionsLet y=0 and solve for x, this is your xintercept 3x3 (0)=6 3x=6 3x/3=6/3 x=2 Plot (2,0) Notice that is the same xintercept that L1 had L1 is lying right ontop of L2, in other words they graphically are the same line The solution is all real numbers
যদি (xy)^(3)(xy)^(3)6y(x^(2)y^(2))=ky^(2) , তারপরে কে = Updated On 23 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!Start your free trial In partnership with You are being redirected to Course Hero I want to The factored form is (x3y)(xy) You can treat it like a quadratic, where instead of constant numbers, there are y terms First, find two numbers that multiply to 3 (the c value of the "quadratic") and add up to 2 (the b value of the "quadratic") These two numbers are 3 and 1 Split the middle term into these two numbers Then, factor the first two and last two terms
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Find stepbystep Calculus solutions and your answer to the following textbook question For what value of k are the two lines 2x ky = 3 and x y = 1 parallel?Subtract x^ {3} from both sides Subtract x 3 from both sides Combine x^ {3} and x^ {3} to get 0 Combine x 3 and − x 3 to get 0 Reorder the terms Reorder the terms This is true for any x This is true for any x Use the distributive property to multiply xy by x^ {2}xyy^ {2This calculator will try to solve the system of 2, 3, 4, 5 simultaneous equations of any kind, including the polynomial, rational, irrational, exponential
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The quadratic x2 2x3 = 0 has no real solutions, so the only solution to the cubic equation is obtained by putting x− 1 = 0, giving the single real solution x = 1 The graph y = x3 x2 x− 3 is shown in Figure 4 2 1 2 3 x y 324 Figure 4 The graph of y = x3 x2 x− 3 You can see that the graph crosses the xaxis in oneSolution 1 First assume y 2 =ux 2, and y 2 '=2uxu'x 2 and y 2 ''=u''x 2 4u'x2u Substituting into x 2 y''2xy'6y=0 we get x 2 (u''x 2 4u'x2u)2x(2uxu'x 2)6y=0 and simplifying by adding like terms we get u''x 4 6u'x 3 =0 We reduce the order by w=u' to get w'x 4 6wx 3 =0 Now dividing by wx 4 and rearranging, we get and integrating bothWatch Video in App This browser does not support the video element 348 k 17 k Answer
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Math Input NEW Use textbook math notation to enter your math Try itSubstitute x in terms of y into the first equation (2y6) 2 y 2 =36 Use FOIL to expand the brackets 4y 2 24y36y 2 =36 => 5y 2 24y=0 y(5y24)=0 => y=0 or y=(24)/5 Substitute these values of y into the second equation to find x when y=0, x=2*06 => x=6 when y=(24)/5, x=2*(24)/56 => x=36(2 x) dy dx = 3y This is a First Order separable Differential equation, and we can rearrange as follows 1 y dy dx = 3 x 2 And we can "separate the variables" to get ∫ 1 y dy = ∫ 3 x 2 dx
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